This document describes Django’s file access APIs for files such as those uploaded by a user. The lower level APIs are general enough that you could use them for other purposes. If you want to handle “static files” (JS, CSS, etc.), see Managing static files (e.g. images, JavaScript, CSS).
By default, Django stores files locally, using the MEDIA_ROOT
and
MEDIA_URL
settings. The examples below assume that you’re using these
defaults.
However, Django provides ways to write custom file storage systems that allow you to completely customize where and how Django stores files. The second half of this document describes how these storage systems work.
When you use a FileField
or
ImageField
, Django provides a set of APIs you can use
to deal with that file.
Consider the following model, using an ImageField
to
store a photo:
from django.db import models
class Car(models.Model):
name = models.CharField(max_length=255)
price = models.DecimalField(max_digits=5, decimal_places=2)
photo = models.ImageField(upload_to='cars')
Any Car
instance will have a photo
attribute that you can use to get at
the details of the attached photo:
>>> car = Car.objects.get(name="57 Chevy")
>>> car.photo
<ImageFieldFile: cars/chevy.jpg>
>>> car.photo.name
'cars/chevy.jpg'
>>> car.photo.path
'/media/cars/chevy.jpg'
>>> car.photo.url
'http://media.example.com/cars/chevy.jpg'
This object – car.photo
in the example – is a File
object, which means
it has all the methods and attributes described below.
Note
The file is saved as part of saving the model in the database, so the actual file name used on disk cannot be relied on until after the model has been saved.
For example, you can change the file name by setting the file’s
name
to a path relative to the file storage’s
location (MEDIA_ROOT
if you are using the default
FileSystemStorage
):
>>> import os
>>> from django.conf import settings
>>> initial_path = car.photo.path
>>> car.photo.name = 'cars/chevy_ii.jpg'
>>> new_path = settings.MEDIA_ROOT + car.photo.name
>>> # Move the file on the filesystem
>>> os.rename(initial_path, new_path)
>>> car.save()
>>> car.photo.path
'/media/cars/chevy_ii.jpg'
>>> car.photo.path == new_path
True
Note
Whilst ImageField
non-image data attributes,
such as height
, width
, and size
are available on the instance,
the underlying image data cannot be used without reopening the image. For
example:
>>> from PIL import Image
>>> car = Car.objects.get(name='57 Chevy')
>>> car.photo.width
191
>>> car.photo.height
287
>>> image = Image.open(car.photo)
# Raises ValueError: seek of closed file.
>>> car.photo.open()
<ImageFieldFile: cars/chevy.jpg>
>>> image = Image.open(car.photo)
>>> image
<PIL.JpegImagePlugin.JpegImageFile image mode=RGB size=191x287 at 0x7F99A94E9048>
File
object¶Internally, Django uses a django.core.files.File
instance any time it
needs to represent a file.
Most of the time you’ll simply use a File
that Django’s given you (i.e. a
file attached to a model as above, or perhaps an uploaded file).
If you need to construct a File
yourself, the easiest way is to create one
using a Python built-in file
object:
>>> from django.core.files import File
# Create a Python file object using open()
>>> f = open('/path/to/hello.world', 'w')
>>> myfile = File(f)
Now you can use any of the documented attributes and methods
of the File
class.
Be aware that files created in this way are not automatically closed. The following approach may be used to close files automatically:
>>> from django.core.files import File
# Create a Python file object using open() and the with statement
>>> with open('/path/to/hello.world', 'w') as f:
... myfile = File(f)
... myfile.write('Hello World')
...
>>> myfile.closed
True
>>> f.closed
True
Closing files is especially important when accessing file fields in a loop over a large number of objects. If files are not manually closed after accessing them, the risk of running out of file descriptors may arise. This may lead to the following error:
IOError: [Errno 24] Too many open files
Behind the scenes, Django delegates decisions about how and where to store files to a file storage system. This is the object that actually understands things like file systems, opening and reading files, etc.
Django’s default file storage is given by the DEFAULT_FILE_STORAGE
setting; if you don’t explicitly provide a storage system, this is the one that
will be used.
See below for details of the built-in default file storage system, and see Writing a custom storage system for information on writing your own file storage system.
Though most of the time you’ll want to use a File
object (which delegates to
the proper storage for that file), you can use file storage systems directly.
You can create an instance of some custom file storage class, or – often more
useful – you can use the global default storage system:
>>> from django.core.files.base import ContentFile
>>> from django.core.files.storage import default_storage
>>> path = default_storage.save('path/to/file', ContentFile(b'new content'))
>>> path
'path/to/file'
>>> default_storage.size(path)
11
>>> default_storage.open(path).read()
b'new content'
>>> default_storage.delete(path)
>>> default_storage.exists(path)
False
See File storage API for the file storage API.
Django ships with a django.core.files.storage.FileSystemStorage
class
which implements basic local filesystem file storage.
For example, the following code will store uploaded files under
/media/photos
regardless of what your MEDIA_ROOT
setting is:
from django.core.files.storage import FileSystemStorage
from django.db import models
fs = FileSystemStorage(location='/media/photos')
class Car(models.Model):
...
photo = models.ImageField(storage=fs)
Custom storage systems work the same way:
you can pass them in as the storage
argument to a
FileField
.
Nov 02, 2020